How tall is Alexander Volkanovski?

Alexander Volkanovski's listed height is 168 cm (5'6"). He is taller than about 6% of men in Australia.

Where 168 cm sits among men in Australia

Taller than about 6% of men in Australia born in 1988 (average 179.1 cm).

About Alexander Volkanovski

Alexander Volkanovski is an Australian professional mixed martial artist. He was born on 29 September 1988 in Wollongong. He competes in the Featherweight division of the Ultimate Fighting Championship (UFC), where he is the current and two-time UFC Featherweight Champion.

Volkanovski is the first Australian-born fighter to win a UFC title, and he is also a former Australian Fighting Championship Featherweight champion. Before his UFC debut he competed as a professional boxer in 2015. He held the UFC's top pound-for-pound ranking during two separate reigns between 2022 and 2023 and was named Fighter of the Year at the World MMA Awards in 2022. He is tied with José Aldo for the most featherweight title victories in UFC history, and is the oldest fighter to win the UFC Featherweight Championship, at age 36.

At a listed 168 cm (5'6"), Volkanovski later became the oldest fighter to successfully defend that title, at 37. As of 16 June 2026 he is ranked number 2 in the UFC men's pound-for-pound rankings.

Frequently asked

How tall is Alexander Volkanovski in feet and inches? Alexander Volkanovski is 5'6" tall, which is 168 cm, 66.1 inches or 1.68 m.

Is Alexander Volkanovski tall for men in Australia? At 168 cm he is taller than about 6% of men in Australia born in 1988, whose average height is 179.1 cm.

Sources

Heights are as publicly listed, rounded to the nearest centimetre; listed heights for public figures are often self-reported. Biographical details adapted from Wikipedia under CC BY-SA 4.0.

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