How tall is Sloane Stephens?

Sloane Stephens's listed height is 170 cm (5'7"). She is taller than about 82% of women in the United States.

Where 170 cm sits among women in the United States

Taller than about 82% of women in the United States born in 1993 (average 163.6 cm).

About Sloane Stephens

Sloane Stephens is an American professional tennis player, born on 20 March 1993 in Plantation. Born to athletic parents, she was introduced to tennis in Fresno, California. She became a promising junior, reaching a junior ranking of world No. 5 and winning three of the four major girls' doubles titles in 2010 with Tímea Babos.

Stephens rose to prominence at 19 by reaching the semifinals of the 2013 Australian Open, defeating world No. 3 Serena Williams on the way. After falling outside the top 25 at the end of 2015, she changed coach to Kamau Murray and won three WTA titles in the first half of 2016, before a foot injury kept her out for months. She won the 2017 US Open in just her fifth tournament back and was named WTA Comeback Player of the Year. In 2018 she won the Miami Open, reached the French Open final and finished runner-up at the WTA Finals.

Stephens has a listed height of 170 cm (5'7"). She has won eight WTA Tour singles titles and reached a career-high ranking of world No. 3.

Frequently asked

How tall is Sloane Stephens in feet and inches? Sloane Stephens is 5'7" tall, which is 170 cm, 66.9 inches or 1.70 m.

Is Sloane Stephens tall for women in the United States? At 170 cm she is taller than about 82% of women in the United States born in 1993, whose average height is 163.6 cm.

Sources

Heights are as publicly listed, rounded to the nearest centimetre; listed heights for public figures are often self-reported. Biographical details adapted from Wikipedia under CC BY-SA 4.0.

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