How tall is James A. Garfield?

James A. Garfield's listed height was 183 cm (6'0"). He was taller than about 95% of men in the United States.

Where 183 cm sits among men in the United States

Taller than about 95% of men in the United States born in 1831 (average 171.1 cm).

About James A. Garfield

James A. Garfield was the 20th president of the United States, serving from March 1881 until his death in September that year. Born on 19 November 1831 in Moreland Hills, he grew up in northeast Ohio. He graduated from Williams College in 1856, studied law and became an attorney. He was also a preacher in the Restoration Movement and president of the Western Reserve Eclectic Institute.

Garfield was elected as a Republican to the Ohio State Senate in 1859, serving until 1861. He was a major general in the Union Army during the American Civil War and fought in the battles of Middle Creek, Shiloh and Chickamauga. Elected to Congress in 1862 to represent Ohio's 19th district, he served nine terms in the House of Representatives and supported the gold standard. The Ohio General Assembly elected him to the U.S. Senate, a position he declined upon becoming president-elect.

Garfield stood at a listed 183 cm (6'0"). He died on 19 September 1881. He is the only sitting member of the House to be elected president, and he published his own proof of the Pythagorean theorem in 1876.

Frequently asked

How tall is James A. Garfield in feet and inches? James A. Garfield was 6'0" tall, which is 183 cm, 72 inches or 1.83 m.

Is James A. Garfield tall for men in the United States? At 183 cm he was taller than about 95% of men in the United States born in 1831, whose average height is 171.1 cm.

Sources

Heights are as publicly listed, rounded to the nearest centimetre; listed heights for public figures are often self-reported. Biographical details adapted from Wikipedia under CC BY-SA 4.0.

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